(* Content-type: application/vnd.wolfram.mathematica *) (*** Wolfram Notebook File ***) (* http://www.wolfram.com/nb *) (* CreatedBy='Mathematica 9.0' *) (*CacheID: 234*) (* Internal cache information: NotebookFileLineBreakTest NotebookFileLineBreakTest NotebookDataPosition[ 157, 7] NotebookDataLength[ 87210, 2898] NotebookOptionsPosition[ 60085, 2103] NotebookOutlinePosition[ 72524, 2446] CellTagsIndexPosition[ 72287, 2436] WindowFrame->Normal*) (* Beginning of Notebook Content *) Notebook[{ Cell[TextData[StyleBox["Symbolick\[EAcute] v\[YAcute]po\[CHacek]ty", \ "Title"]], "OverviewSection", CellChangeTimes->{{3.578380596078125*^9, 3.5783806211875*^9}}, TextAlignment->Center, CellTags->"Overview"], Cell["Obsah", "Text", CellChangeTimes->{{3.578380633609375*^9, 3.578380634265625*^9}}], Cell[TextData[{ StyleBox["Mathematica", FontSlant->"Italic"], " obsahuje funkce pro v\[SHacek]echny symbolick\[EAcute] operace, pro kter\ \[EAcute] existuje obecn\[YAcute] 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Toto d\[EHacek]l\ \[AAcute] ", Cell[BoxData[ ButtonBox["ExpandAll", BaseStyle->"Link", ButtonData->"paclet:ref/ExpandAll"]], "InlineFormula"], "." }], "MathCaption", CellChangeTimes->{{3.579336443890625*^9, 3.5793364650625*^9}}], Cell[BoxData[ RowBox[{"Expand", "[", SqrtBox[ SuperscriptBox[ RowBox[{"(", RowBox[{"1", "+", "x"}], ")"}], "2"]], "]"}]], "Input"], Cell[BoxData[ RowBox[{"ExpandAll", "[", SqrtBox[ SuperscriptBox[ RowBox[{"(", RowBox[{"1", "+", "x"}], ")"}], "2"]], "]"}]], "Input"], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["Polynomy: ", "Color7", FontSlant->"Plain"], "Dal\[SHacek]\[IAcute] operace s polynomy" }], "Subsection", CellChangeTimes->{{3.57933655221875*^9, 3.5793365535*^9}, { 3.579336600734375*^9, 3.57933660634375*^9}}, CellTags->"Polynomials"], Cell["\<\ Racion\[AAcute]ln\[IAcute] funkce je pod\[IAcute]l dvou polynom\[URing]\ \>", "Text", CellChangeTimes->{{3.5793378443125*^9, 3.57933786059375*^9}}, CellTags->"Polynomials"], Cell[TextData[{ "Funkce ", Cell[BoxData[ ButtonBox["Together", BaseStyle->"Link", ButtonData->"paclet:ref/Together"]], "InlineFormula"], " s\[CHacek]\[IAcute]t\[AAcute] racion\[AAcute]ln\[IAcute] funkce \ p\[RHacek]es spole\[CHacek]n\[YAcute] jmenovatel." }], "MathCaption", CellChangeTimes->{{3.579337871265625*^9, 3.579337917640625*^9}}, CellTags->"Polynomials"], Cell[BoxData[ RowBox[{"expr", "=", RowBox[{"Together", "[", RowBox[{ FractionBox["1", "x"], "+", FractionBox["1", RowBox[{"x", "+", "1"}]], "+", FractionBox["1", RowBox[{"x", "+", "2"}]]}], "]"}]}]], "Input", CellTags->"Polynomials"], Cell[TextData[{ "Funkce ", Cell[BoxData[ ButtonBox["Apart", BaseStyle->"Link", ButtonData->"paclet:ref/Apart"]], "InlineFormula"], " provede dekompozici v\[YAcute]razu na zlomky" }], "MathCaption", CellChangeTimes->{{3.57933792196875*^9, 3.579337933609375*^9}, { 3.579337970953125*^9, 3.579337984609375*^9}}, CellTags->"Polynomials"], Cell[BoxData[ RowBox[{"Apart", "[", "expr", "]"}]], "Input", CellChangeTimes->{{3.579338023765625*^9, 3.57933803296875*^9}}], Cell[TextData[{ "N\[AAcute]sleduj\[IAcute]c\[IAcute] je d\[EHacek]len\[IAcute] polynom\ \[URing] ", Cell[BoxData[ FormBox[ SuperscriptBox["x", "2"], TraditionalForm]], "InlineMath"], " d\[EHacek]leno ", Cell[BoxData[ FormBox[ RowBox[{"x", "+", "a"}], TraditionalForm]], "InlineMath"], ", zbytek nen\[IAcute] uva\[ZHacek]ov\[AAcute]n." }], "MathCaption", CellChangeTimes->{{3.57933806578125*^9, 3.579338107296875*^9}, { 3.579338141296875*^9, 3.579338142078125*^9}}, CellID->636777077], Cell[BoxData[ RowBox[{"PolynomialQuotient", "[", RowBox[{ RowBox[{"x", "^", "2"}], ",", RowBox[{"x", "+", "a"}], ",", "x"}], "]"}]], "Input", CellID->76283391], Cell["Vrac\[IAcute] zbytek po d\[EAcute]len\[IAcute]", "MathCaption", CellChangeTimes->{{3.57933824596875*^9, 3.579338253921875*^9}}], Cell[BoxData[ RowBox[{"PolynomialRemainder", "[", RowBox[{ RowBox[{"x", "^", "2"}], ",", RowBox[{"x", "+", "a"}], ",", "x"}], "]"}]], "Input", CellID->2125016089], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell["\[CapitalRHacek]e\[SHacek]en\[IAcute] rovnic", "Section", CellChangeTimes->{{3.57933832421875*^9, 3.5793383296875*^9}}, CellTags->"Solving Equations"], Cell["Obsah", "OverviewSubsection", CellChangeTimes->{{3.5793383368125*^9, 3.579338340203125*^9}}, CellTags->"Solving Equations"], Cell[CellGroupData[{ Cell[TextData[{ "\[RHacek]e\[SHacek]en\[IAcute] rovnic\[LongDash]", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], ", ", Cell[BoxData[ ButtonBox["Reduce", BaseStyle->"Link", ButtonData->"paclet:ref/Reduce"]], "InlineFormula"], ", a ", Cell[BoxData[ ButtonBox["RSolve", BaseStyle->"Link", ButtonData->"paclet:ref/RSolve"]], "InlineFormula"] }], "Item", CellChangeTimes->{{3.579338344234375*^9, 3.5793383508125*^9}}, CellTags->"Solving Equations"], Cell["pr\[AAcute]ce s \[RHacek]e\[SHacek]en\[IAcute]mi rovnic", "Item", CellChangeTimes->{{3.5793383543125*^9, 3.579338363796875*^9}}, CellTags->"Solving Equations"] }, Open ]], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["\[CapitalRHacek]e\[SHacek]en\[IAcute] rovnic: ", "Color7", FontSlant->"Plain"], "Solve" }], "Subsection", CellChangeTimes->{{3.579338374375*^9, 3.5793383805*^9}}, CellTags->"Solving Equations"], Cell[TextData[{ "Funkce ", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], " je implementov\[AAcute]na prim\[AAcute]rn\[EHacek] pro \ \[RHacek]e\[SHacek]en\[IAcute] soustav polynomy\[AAcute]ln\[IAcute]ch rovnic. 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Tato rovnice \ je \[RHacek]e\:015ben\[IAcute] s pomoc\[IAcute] polynomu ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], " a pot\[EAcute] s pou\[ZHacek]it\[IAcute]m ", Cell[BoxData[ ButtonBox["ArcCos", BaseStyle->"Link", ButtonData->"paclet:ref/ArcCos"]], "InlineFormula"], "." }], "MathCaption", CellChangeTimes->{{3.579338695125*^9, 3.579338778671875*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"Solve", "[", RowBox[{ RowBox[{ SuperscriptBox[ RowBox[{"Cos", "[", "x", "]"}], "2"], "\[Equal]", "b"}], ",", "x"}], "]"}]], "Input", CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{ RowBox[{"%", "/.", RowBox[{ RowBox[{"C", "[", "1", "]"}], "\[Rule]", "1"}]}], "//", "Simplify"}]], "Input", CellChangeTimes->{{3.579338798*^9, 3.57933881228125*^9}, {3.579338850125*^9, 3.57933885628125*^9}}], Cell["", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["\[CapitalRHacek]e\[SHacek]en\[IAcute] rovnic: ", "Color7", FontSlant->"Plain"], "Reduce" }], "Subsection", CellChangeTimes->{{3.579338940453125*^9, 3.579338947609375*^9}, { 3.579339005*^9, 3.57933900584375*^9}}, CellTags->"Solving Equations"], Cell[TextData[{ "Zat\[IAcute]mco ", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], " generuje v\[SHacek]echna standardn\[IAcute] \ \[RHacek]e\[SHacek]en\[IAcute], ", Cell[BoxData[ ButtonBox["Reduce", BaseStyle->"Link", ButtonData->"paclet:ref/Reduce"]], "InlineFormula"], " vrac\[IAcute] \[RHacek]e\[SHacek]en\[IAcute] pro v\[SHacek]echny prom\ \[EHacek]nn\[EAcute]." }], "Text", CellChangeTimes->{{3.579338973453125*^9, 3.57933902303125*^9}, { 3.579339158984375*^9, 3.579339170078125*^9}, {3.579339450359375*^9, 3.5793394819375*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ SuperscriptBox[ RowBox[{"Cos", "[", "x", "]"}], "2"], "\[Equal]", "b"}], ",", "x"}], "]"}]], "Input", CellTags->"Solving Equations"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Solve", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "-", RowBox[{"y", "^", "3"}]}], "\[Equal]", "1"}], ",", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.579339238359375*^9, 3.579339273375*^9}}], Cell[BoxData[ RowBox[{ StyleBox[ RowBox[{"Solve", "::", "svars"}], "MessageName"], RowBox[{ ":", " "}], "\<\"Equations may not give solutions for all \\\"solve\\\" \ variables. \\!\\(\\*ButtonBox[\\\"\[RightSkeleton]\\\", ButtonStyle->\\\"Link\ \\\", ButtonFrame->None, ButtonData:>\\\"paclet:ref/message/Solve/svars\\\", \ ButtonNote -> \\\"Solve::svars\\\"]\\)\"\>"}]], "Message", "MSG", CellChangeTimes->{3.57933927409375*^9}] }, Open ]], Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "-", RowBox[{"y", "^", "3"}]}], "\[Equal]", "1"}], ",", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.579339406625*^9, 3.5793394121875*^9}}], Cell["\<\ Mnoho nepolynomi\[AAcute]ln\[IAcute]ch rovnic je trnascendent\[AAcute]ln\ \[IAcute]ch a nemohou b\[YAcute]t \[RHacek]e\[SHacek]eny \ algebraick\[YAcute]mi metodami. \ \>", "MathCaption", CellChangeTimes->{{3.57933953734375*^9, 3.579339583640625*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"Solve", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"2", " ", RowBox[{"Sin", "[", RowBox[{"Exp", "[", "z", "]"}], "]"}]}], "-", RowBox[{"Cos", "[", RowBox[{"\[Pi]", " ", "z"}], "]"}]}], "==", FractionBox["1", "3"]}], ",", "z"}], "]"}]], "Input", CellChangeTimes->{3.579339596125*^9}], Cell[TextData[{ StyleBox["Mathematica", FontSlant->"Italic"], " nalezne ko\[RHacek]eny t\[EHacek]chto transcendent\[AAcute]ln\[IAcute]ch \ rovnic a\[CHacek]koliv jsou repreznetov\[AAcute]ny jako ", Cell[BoxData[ ButtonBox["Root", BaseStyle->"Link", ButtonData->"paclet:ref/Root"]], "InlineFormula"], " objekty. " }], "MathCaption", CellChangeTimes->{{3.579339617125*^9, 3.57933965865625*^9}}], Cell[BoxData[ RowBox[{"rts", "=", RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"2", " ", RowBox[{"Sin", "[", RowBox[{"Exp", "[", "z", "]"}], "]"}]}], "-", RowBox[{"Cos", "[", RowBox[{"\[Pi]", " ", "z"}], "]"}]}], "==", FractionBox["1", "3"]}], "&&", RowBox[{ RowBox[{"Abs", "[", "z", "]"}], "<", "1"}]}], ",", "z"}], "]"}]}]], "Input"], Cell["\<\ N\[AAcute]sleduj\[IAcute]c\[IAcute] konvertuje ko\[RHacek]eny na explicitn\ \[IAcute] \[CHacek]\[IAcute]sla.\ \>", "MathCaption", CellChangeTimes->{{3.57933970546875*^9, 3.5793397281875*^9}}], Cell[BoxData[ RowBox[{"N", "[", "rts", "]"}]], "Input"], Cell[BoxData[ RowBox[{"Clear", "[", RowBox[{"soln", ",", "expr", ",", "rts", ",", "f"}], "]"}]], "Input"], Cell["", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["\[CapitalRHacek]e\[SHacek]en\[IAcute] rovnic: ", "Color7", FontSlant->"Plain"], "RSolve" }], "Subsection", CellChangeTimes->{{3.57933998125*^9, 3.579339993171875*^9}}, CellTags->"Solving Equations"], Cell[TextData[{ "Rekurentn\[IAcute] rovnice (diferen\[CHacek]n\[IAcute] rovnice 1. \[RHacek]\ \[AAcute]du) mohou b\[YAcute]t \[RHacek]e\[SHacek]eny s pou\[ZHacek]it\ \[IAcute]m ", Cell[BoxData[ ButtonBox["RSolve", BaseStyle->"Link", ButtonData->"paclet:ref/RSolve"]], "InlineFormula"], ". N\[AAcute]sleduj\[IAcute]c\[IAcute], nap\[RHacek]\[IAcute]klad \[RHacek]e\ \[SHacek]\[IAcute] logistick\[EAcute] rovnice pomoc\[IAcute] trigonometrick\ \[YAcute]ch funkc\[IAcute]." }], "Text", CellChangeTimes->{{3.57934002584375*^9, 3.579340115671875*^9}, { 3.57984254028125*^9, 3.579842563546875*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"RSolve", "[", RowBox[{ RowBox[{ RowBox[{"x", "[", RowBox[{"k", "+", "1"}], "]"}], "\[Equal]", RowBox[{"4", " ", RowBox[{"x", "[", "k", "]"}], " ", RowBox[{"(", RowBox[{"1", "-", RowBox[{"x", "[", "k", "]"}]}], ")"}]}]}], ",", RowBox[{"x", "[", "k", "]"}], ",", "k"}], "]"}]], "Input", CellTags->"Solving Equations"], Cell["\<\ N\[AAcute]sleduj\[IAcute]c\[IAcute] \[RHacek]e\[SHacek]en\[IAcute] rekurentn\ \[IAcute]ch rovnic vede na Fibonacciho posloupnost. \ \>", "MathCaption", CellChangeTimes->{{3.35627132490016*^9, 3.35627135479314*^9}, { 3.579340189640625*^9, 3.579340240796875*^9}, {3.579842577265625*^9, 3.57984258684375*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"RSolve", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{"f", "[", "n", "]"}], "==", RowBox[{ RowBox[{"f", "[", RowBox[{"n", "-", "1"}], "]"}], "+", RowBox[{"f", "[", RowBox[{"n", "-", "2"}], "]"}]}]}], ",", RowBox[{ RowBox[{"f", "[", "1", "]"}], "==", "1"}], ",", RowBox[{ RowBox[{"f", "[", "2", "]"}], "==", "1"}]}], "}"}], ",", RowBox[{"f", "[", "n", "]"}], ",", "n"}], "]"}]], "Input", CellTags->"Solving Equations"], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["\[CapitalRHacek]e\[SHacek]en\[IAcute] rovnic: ", "Color7", FontSlant->"Plain"], "Pou\[ZHacek]it\[IAcute] seznamu pravidel" }], "Subsection", CellChangeTimes->{{3.57934025978125*^9, 3.57934027428125*^9}}, CellTags->"Solving Equations"], Cell[TextData[{ "Mnoho funkc\[IAcute] v ", StyleBox["Mathematica", FontSlant->"Italic"], " generuje v\[YAcute]stup ve form\[EHacek] seznamu pravidel. Nap\[RHacek]\ \[IAcute]klad v\[YAcute]stup funkce ", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], " je seznam \[RHacek]e\[SHacek]en\[IAcute], kter\[EAcute] ka\[ZHacek]d\ \[EAcute] je reprezentov\[AAcute]no jako pravidlo ve tvaru ", StyleBox["var\[ThinSpace]", FontSlant->"Italic"], "\[Rule]\[ThinSpace]", StyleBox["expr", FontSlant->"Italic"], ". \[CapitalCHacek]asto je t\[RHacek]eba z\[IAcute]skat samostatn\[EAcute] v\ \[YAcute]razy na prav\[EAcute] stran\[EHacek] t\[EHacek]chto pravidel a pou\ \[ZHacek]\[IAcute]t je v dal\[SHacek]\[IAcute]ch v\[YAcute]po\[CHacek]tech. " }], "Text", CellChangeTimes->{{3.579340279234375*^9, 3.57934042609375*^9}}, CellTags->"Solving Equations"], Cell["\<\ Zde je soustava rovnic, kter\[AAcute] m\[AAcute] 4 \[RHacek]e\[SHacek]en\ \[IAcute] dan\[YAcute]ch pravidly.\ \>", "MathCaption", CellChangeTimes->{{3.579347532265625*^9, 3.579347561578125*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"soln", "=", RowBox[{"Solve", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], "\[Equal]", "1"}], ",", RowBox[{ RowBox[{"y", "-", RowBox[{"2", " ", SuperscriptBox["x", "2"]}], "+", FractionBox["3", "2"]}], "\[Equal]", "0"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}]}], "]"}]}]], "Input", CellTags->"Solving Equations"], Cell["\<\ N\[AAcute]sleduj\[IAcute]c\[IAcute] p\[RHacek]\[IAcute]kaz vykresl\[IAcute] \ ob\[EHacek] k\[RHacek]ivky dan\[EAcute] rovnicemi.\ \>", "MathCaption", CellChangeTimes->{{3.579347573703125*^9, 3.579347594109375*^9}}], Cell[BoxData[ RowBox[{"ContourPlot", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], "\[Equal]", "1"}], ",", RowBox[{ RowBox[{"y", "-", RowBox[{"2", " ", SuperscriptBox["x", "2"]}], "+", FractionBox["3", "2"]}], "\[Equal]", "0"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "1.5"}], ",", "1.5"}], "}"}], ",", RowBox[{"{", RowBox[{"y", ",", RowBox[{"-", "1.5"}], ",", "1.5"}], "}"}]}], "]"}]], "Input", CellChangeTimes->{3.579347609296875*^9}], Cell["\<\ P\[RHacek]edpokl\[AAcute]dejme, \[ZHacek]e chceme vykreslit tato 4 \[RHacek]e\ \[SHacek]en\[IAcute] spolu s grafy obou k\[RHacek]ivek. Nejprve z\[IAcute]sk\ \[AAcute]me hodnoty \[RHacek]e\[SHacek]en\[IAcute] na prav\[YAcute]ch stran\ \[AAcute]ch pravidel.\ \>", "MathCaption", CellChangeTimes->{{3.579347620421875*^9, 3.57934768925*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{ RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}], "/.", "soln"}]], "Input", CellTags->"Solving Equations"], Cell[TextData[{ "Pomoc\[IAcute] takto z\[IAcute]skan\[YAcute]ch sou\[RHacek]adnic \[RHacek]e\ \[SHacek]en\[IAcute] a grafick\[EAcute]ho primitivu ", Cell[BoxData[ ButtonBox["Point", BaseStyle->"Link", ButtonData->"paclet:ref/Point"]], "InlineFormula"], " vykresl\[IAcute]me po\[ZHacek]adovan\[EAcute] body \[RHacek]e\[SHacek]en\ \[IAcute] do grafu." }], "MathCaption", CellChangeTimes->{{3.579347702328125*^9, 3.579347750734375*^9}}], Cell[BoxData[ RowBox[{ RowBox[{"Point", "[", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}], "]"}], "/.", "soln"}]], "Input"], Cell[BoxData[ RowBox[{"ContourPlot", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], "\[Equal]", "1"}], ",", RowBox[{ RowBox[{"y", "-", RowBox[{"2", " ", SuperscriptBox["x", "2"]}], "+", FractionBox["3", "2"]}], "\[Equal]", "0"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "1.5"}], ",", "1.5"}], "}"}], ",", RowBox[{"{", RowBox[{"y", ",", RowBox[{"-", "1.5"}], ",", "1.5"}], "}"}], ",", RowBox[{"Epilog", "\[Rule]", RowBox[{"{", RowBox[{"Red", ",", RowBox[{"PointSize", "[", ".025", "]"}], ",", RowBox[{ RowBox[{"Point", "[", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}], "]"}], "/.", "soln"}]}], "}"}]}]}], "]"}]], "Input"], Cell["\<\ Uvoln\[IAcute]me v\[SHacek]echny pou\[ZHacek]it\[EAcute] symboly.\ \>", "MathCaption", CellChangeTimes->{{3.57934777253125*^9, 3.57934779478125*^9}}, CellTags->"Solving Equations"], Cell[BoxData[ RowBox[{"Clear", "[", RowBox[{"soln", ",", "poly", ",", "expr", ",", "fib"}], "]"}]], "Input", CellTags->"Solving Equations"], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell["Kalkulus", "Section", CellChangeTimes->{{3.57934780021875*^9, 3.579347801453125*^9}}, CellTags->"Calculus"], Cell["Obsah", "OverviewSubsection", CellChangeTimes->{{3.579347987625*^9, 3.579347989984375*^9}}, CellTags->"Calculus"], Cell[CellGroupData[{ Cell[TextData[{ "integr\[AAcute]l, ur\[CHacek]it\[YAcute] a neur\[CHacek]it\[YAcute]\ \[LongDash]", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]]] }], "Item", CellChangeTimes->{{3.57934799553125*^9, 3.5793480136875*^9}, { 3.57934814378125*^9, 3.579348149390625*^9}}, CellTags->"Calculus"], Cell["\<\ vlo\[ZHacek]en\[IAcute] znaku integr\[AAcute]lu z palety nebo z \ kl\[AAcute]vesnice\ \>", "Item", CellChangeTimes->{{3.579348021296875*^9, 3.5793480420625*^9}}, CellTags->"Calculus"], Cell[TextData[{ "derivace\[LongDash]", Cell[BoxData[ ButtonBox["D", BaseStyle->"Link", ButtonData->"paclet:ref/D"]], "InlineFormula"] }], "Item", CellChangeTimes->{{3.579348045296875*^9, 3.57934804684375*^9}}, CellTags->"Calculus"], Cell[TextData[{ "diferenci\[AAcute]ln\[IAcute] rovnice\[LongDash]", Cell[BoxData[ ButtonBox["DSolve", BaseStyle->"Link", ButtonData->"paclet:ref/DSolve"]]] }], "Item", CellChangeTimes->{{3.579348051984375*^9, 3.579348057875*^9}}, CellTags->"Calculus"], Cell[TextData[{ "limity a \[RHacek]ady\[LongDash]", Cell[BoxData[ ButtonBox["Limit", BaseStyle->"Link", ButtonData->"paclet:ref/Limit"]], "InlineFormula"], " a ", Cell[BoxData[ ButtonBox["Series", BaseStyle->"Link", ButtonData->"paclet:ref/Series"]]] }], "Item", CellChangeTimes->{{3.579348060609375*^9, 3.579348070078125*^9}}, CellTags->"Calculus"] }, Open ]], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["Kalkulus: ", "Color7", FontSlant->"Plain"], "Symbolick\[YAcute] integr\[AAcute]l" }], "Subsection", CellChangeTimes->{{3.579348073171875*^9, 3.5793480885*^9}}, CellTags->"Calculus"], Cell[TextData[{ "Symbolick\[YAcute] integr\[AAcute]l je ur\[CHacek]en \ pou\[ZHacek]it\[IAcute]m funkce ", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]], "InlineFormula"], "." }], "Text", CellChangeTimes->{{3.57934809153125*^9, 3.57934811271875*^9}}, CellTags->"Calculus"], Cell["\<\ N\[AAcute]sleduj\[IAcute]c\[IAcute] vypo\[CHacek]te neur\[CHacek]it\[YAcute] \ integral.\ \>", "MathCaption", CellChangeTimes->{{3.57934811640625*^9, 3.57934813665625*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{"x", " ", RowBox[{"Cos", "[", "x", "]"}]}], ",", "x"}], "]"}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "Pokud druh\[YAcute] argument obsahuje meze integr\[AAcute]lu, potom funkce ", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]], "InlineFormula"], " vrac\[IAcute] ur\[CHacek]it\[YAcute] integr\[AAcute]l." }], "MathCaption", CellChangeTimes->{{3.579348161234375*^9, 3.57934819590625*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{"x", " ", RowBox[{"Cos", "[", "x", "]"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "\[Alpha]", ",", "\[Beta]"}], "}"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell["\<\ V\[SHacek]imn\[EHacek]me si, \[ZHacek]e integr\[AAcute]l je mo\[ZHacek]n\ \[EAcute] vlo\[ZHacek]it pomoc\[IAcute] tradi\[CHacek]n\[IAcute] notace. \ Tento vstup je ekvivalentn\[IAcute] p\[RHacek]\[IAcute]kazu z p\[RHacek]edch\ \[AAcute]zej\[IAcute]c\[IAcute]ho p\[RHacek]\[IAcute]kladu.\ \>", "MathCaption", CellChangeTimes->{{3.579348203703125*^9, 3.5793482534375*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{ SubsuperscriptBox["\[Integral]", "\[Alpha]", "\[Beta]"], RowBox[{"x", " ", RowBox[{"Cos", "[", "x", "]"}], RowBox[{"\[DifferentialD]", "x"}]}]}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "Mnoho symbolick\[YAcute]ch integr\[AAcute]l\[URing] s parametry \ nen\[IAcute] mo\[ZHacek]n\[EAcute] symbolicky ur\[CHacek]it bez \ dopl\[NHacek]uj\[IAcute]c\[IAcute] informace o t\[EHacek]chto parametrech. \ Nastaven\[IAcute] ", Cell[BoxData[ ButtonBox["Assumptions", BaseStyle->"Link", ButtonData->"paclet:ref/Assumptions"]], "InlineFormula"], " je pou\[ZHacek]ito ve funkci ", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]], "InlineFormula"], " ke specifikaci informace o dom\[EAcute]n\[EHacek] parametr\[URing] v \ integrandu." }], "Text", CellChangeTimes->{{3.57934826065625*^9, 3.579348397546875*^9}}, CellTags->"Calculus"], Cell["\<\ Nap\[RHacek]\[IAcute]klad n\[AAcute]sleduj\[IAcute]c\[IAcute] \ integr\[AAcute]l nelze ur\[CHacek]it bez dodate\[CHacek]n\[EAcute]m \ p\[RHacek]edpokladu o parametru c.\ \>", "MathCaption", CellChangeTimes->{{3.579348401984375*^9, 3.579348447859375*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{"Exp", "[", RowBox[{"a", " ", SuperscriptBox["x", "2"]}], "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "\[Infinity]"}], "}"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "Ale s p\[RHacek]edpokladem ", Cell[BoxData[ FormBox[ RowBox[{"a", "<", "0"}], TraditionalForm]]], " tje mo\[ZHacek]n\[EAcute] integr\[AAcute]l kompletn\[EHacek] ur\[CHacek]it." }], "MathCaption", CellChangeTimes->{{3.579348452703125*^9, 3.579348477828125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{"Exp", "[", RowBox[{"a", " ", SuperscriptBox["x", "2"]}], "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "\[Infinity]"}], "}"}], ",", RowBox[{"Assumptions", "\[Rule]", RowBox[{"a", "<", "0"}]}]}], "]"}]], "Input", CellTags->"Calculus"], Cell["\<\ M\[URing]\[ZHacek]eme integrovat multidimenzion\[AAcute]ln\[IAcute] integr\ \[AAcute]ly specifikac\[IAcute] hranic pro ka\[ZHacek]dou prom\[EHacek]nnou.\ \>", "Text", CellChangeTimes->{{3.579348563015625*^9, 3.57934860959375*^9}}, CellTags->"Calculus"], Cell[TextData[{ "N\[AAcute]sleduj\[IAcute]c\[IAcute] ur\[CHacek]\[IAcute] multiple integr\ \[AAcute]l ", Cell[BoxData[ FormBox[ RowBox[{ SubsuperscriptBox["\[Integral]", "0", "1"], RowBox[{ RowBox[{"\[DifferentialD]", "x"}], RowBox[{ SubsuperscriptBox["\[Integral]", "0", StyleBox["x", "TI"]], RowBox[{ RowBox[{"\[DifferentialD]", "y"}], " ", RowBox[{"(", RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox[ StyleBox["y", "TI"], "2"]}], ")"}]}]}]}]}], TraditionalForm]], "InlineFormula"], ". Rozsah vn\[EHacek]j\[SHacek]\[IAcute] prom\[EHacek]nn\[EAcute] se uv\ \[AAcute]d\[IAcute] jako prvn\[IAcute]. " }], "MathCaption", CellChangeTimes->{{3.5793486145*^9, 3.579348674703125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "1"}], "}"}], ",", RowBox[{"{", RowBox[{"y", ",", "0", ",", "x"}], "}"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "Tento p\[RHacek]\[IAcute]kaz integruje ", Cell[BoxData[ FormBox[ SuperscriptBox["x", "2"], TraditionalForm]]], " na oblasti jednotkov\[EAcute]ho kruhu s vyu\[ZHacek]it\[IAcute]m funkce \ Boolean k definici t\[EAcute]to oblasti. ", StyleBox["Boole[", "MR"], StyleBox["expr", "IT"], StyleBox["]", "MR"], " vrac\[IAcute] 1 kdykoliv je ", StyleBox["expr", FontSlant->"Italic"], " ", Cell[BoxData[ ButtonBox["True", BaseStyle->"Link", ButtonData->"paclet:ref/True"]], "InlineFormula"], " a vrac\[IAcute] 0 pokud je ", StyleBox["expr", FontSlant->"Italic"], " ", Cell[BoxData[ ButtonBox["False", BaseStyle->"Link", ButtonData->"paclet:ref/False"]], "InlineFormula"], "." }], "MathCaption", CellChangeTimes->{{3.579348682046875*^9, 3.579348809421875*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{ SuperscriptBox["x", "2"], RowBox[{"Boole", "[", RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], "<", "1"}], "]"}]}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "1"}], ",", "1"}], "}"}], ",", RowBox[{"{", RowBox[{"y", ",", RowBox[{"-", "1"}], ",", "1"}], "}"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["Kalkulus: ", "Color7", FontSlant->"Plain"], "Derivace" }], "Subsection", CellChangeTimes->{{3.5793488185625*^9, 3.5793488246875*^9}}, CellTags->"Calculus"], Cell[TextData[{ "Derivaci je mo\[ZHacek]n\[EAcute] ur\[CHacek]it pomoc\[IAcute] funkce ", Cell[BoxData[ ButtonBox["D", BaseStyle->"Link", ButtonData->"paclet:ref/D"]], "InlineFormula"], "." }], "Text", CellChangeTimes->{{3.57934883053125*^9, 3.57934884959375*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"D", "[", RowBox[{ RowBox[{"x", " ", RowBox[{"Cos", "[", "x", "]"}]}], ",", "x"}], "]"}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "Je mo\[ZHacek]n\[EAcute] po\[CHacek]\[IAcute]tat i derivace vy\[SHacek]\ \[SHacek]\[IAcute]ch \[RHacek]\[AAcute]d\[URing] s pou\[ZHacek]it\[IAcute]m \ formy ", Cell[BoxData[ RowBox[{"D", "[", RowBox[{ StyleBox["fun", "TI"], ",", RowBox[{"{", RowBox[{ StyleBox["x", "TI"], ",", StyleBox["n", "TI"]}], "}"}]}], "]"}]]], "." }], "MathCaption", CellChangeTimes->{{3.579348874328125*^9, 3.57934890346875*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"D", "[", RowBox[{ SuperscriptBox["x", "5"], ",", RowBox[{"{", RowBox[{"x", ",", "2"}], "}"}]}], "]"}]], "Input"], Cell["\<\ M\[URing]\[ZHacek]eme po\[CHacek]\[IAcute]tat i parci\[AAcute]ln\[IAcute] \ derivace.\ \>", "MathCaption", CellChangeTimes->{{3.579348912734375*^9, 3.579348941453125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"D", "[", RowBox[{ RowBox[{"Sin", "[", RowBox[{"x", " ", "y"}], "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "2"}], "}"}], ",", RowBox[{"{", RowBox[{"y", ",", "1"}], "}"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell["\<\ Nebo je mo\[ZHacek]n\[EAcute] pou\[ZHacek]\[IAcute]t trad\[CHacek]n\[IAcute] \ notaci (snadno dostupnou z palet).\ \>", "MathCaption", CellChangeTimes->{{3.579348946265625*^9, 3.579348973734375*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{ SubscriptBox["\[PartialD]", RowBox[{"x", ",", "x", ",", "y"}]], RowBox[{"Sin", "[", RowBox[{"x", " ", "y"}], "]"}]}]], "Input", CellTags->"Calculus"], Cell["\<\ Lze pou\[ZHacek]\[IAcute]t tak\[EAcute] tradi\[CHacek]n\[IAcute] notaci k v\ \[YAcute]po\[CHacek]tu derivace funkce.\ \>", "MathCaption", CellChangeTimes->{{3.579348992609375*^9, 3.57934902340625*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{ RowBox[{"Cos", "'"}], "[", "x", "]"}]], "Input", CellTags->"Calculus"], Cell[BoxData[ RowBox[{ RowBox[{"f", "[", "x_", "]"}], ":=", RowBox[{ SuperscriptBox["x", "5"], "-", RowBox[{"10", SuperscriptBox["x", "4"]}], "+", SuperscriptBox["x", "3"]}]}]], "Input", CellTags->"Calculus"], Cell[BoxData[ RowBox[{ RowBox[{"f", "'"}], "[", "x", "]"}]], "Input", CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Clear", "[", "f", "]"}]], "Input", CellChangeTimes->{{3.391870571526393*^9, 3.3918705747436123`*^9}}], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["Kalkulus: ", "Color7", FontSlant->"Plain"], "Diferenci\[AAcute]ln\[IAcute] rovnice" }], "Subsection", CellChangeTimes->{{3.579842518359375*^9, 3.579842521171875*^9}, { 3.5798426110625*^9, 3.579842618390625*^9}}, CellTags->"Calculus"], Cell[TextData[{ "Symbolick\[EAcute] \[RHacek]e\[SHacek]en\[IAcute] diferenci\[AAcute]ln\ \[IAcute]ch rovnic je mo\[ZHacek]n\[EAcute] vypo\[CHacek]\[IAcute]tat pomoc\ \[IAcute] funkce ", Cell[BoxData[ ButtonBox["DSolve", BaseStyle->"Link", ButtonData->"paclet:ref/DSolve"]], "InlineFormula"], "." }], "Text", CellChangeTimes->{{3.57984336621875*^9, 3.57984339634375*^9}}, CellTags->"Calculus"], Cell[TextData[{ "N\[AAcute]sleduj\[IAcute]c\[IAcute] \[RHacek]e\[SHacek]\[IAcute] diferenci\ \[AAcute]ln\[IAcute] rovnici ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["f", "\[Prime]\[Prime]"], "(", "x", ")"}], "+", RowBox[{"f", "(", "x", ")"}]}], "=", "0"}], TraditionalForm]]], ". Prvn\[IAcute] argument funkce ", Cell[BoxData[ ButtonBox["DSolve", BaseStyle->"Link", ButtonData->"paclet:ref/DSolve"]], "InlineFormula"], " je diferenci\[AAcute]ln\[IAcute] rovnice, druh\[YAcute] specifikuje \ hledanou funkci, t\[RHacek]et\[IAcute] argument ur\[CHacek]uje \ prom\[EHacek]nou. V\[YAcute]sledek je d\[AAcute]n pravidly stejn\[EHacek] tak \ jako v\[YAcute]sledek z funkce ", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], "." }], "MathCaption", CellChangeTimes->{{3.579843405609375*^9, 3.579843500671875*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"DSolve", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"f", "''"}], "[", "x", "]"}], "+", RowBox[{"f", "[", "x", "]"}]}], "\[Equal]", "0"}], ",", RowBox[{"f", "[", "x", "]"}], ",", "x"}], "]"}]], "Input", CellTags->"Calculus"], Cell["\<\ Omezen\[IAcute] a po\[CAcute]\[AAcute]te\[CHacek]n\[IAcute] podm\[IAcute]nky \ mohou b\[YAcute]t zahrnuty pou\[ZHacek]it\[IAcute] dal\[SHacek]\[IAcute]ch \ rovnic.\ \>", "MathCaption", CellChangeTimes->{{3.57984351215625*^9, 3.57984354578125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"DSolve", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"f", "''"}], "[", "x", "]"}], "+", RowBox[{"f", "[", "x", "]"}]}], "\[Equal]", "0"}], ",", RowBox[{ RowBox[{"f", "[", "0", "]"}], "\[Equal]", "0"}], ",", RowBox[{ RowBox[{ RowBox[{"f", "'"}], "[", "0", "]"}], "\[Equal]", "1"}]}], "}"}], ",", RowBox[{"f", "[", "x", "]"}], ",", "x"}], "]"}]], "Input", CellTags->"Calculus"], Cell["\<\ Zde je neline\[AAcute]rn\[IAcute] diferenci\[AAcute]ln\[IAcute] rovnice 1. \ \[RHacek]\[AAcute]du. V t\[EHacek]chto p\[RHacek]\[IAcute]padech je nalezen\ \[IAcute] \[RHacek]e\[SHacek]en\[IAcute] snadn\[EAcute].\ \>", "MathCaption", CellChangeTimes->{{3.579843572921875*^9, 3.5798435995*^9}, { 3.57984364996875*^9, 3.57984366646875*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"soln", "=", RowBox[{"DSolve", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["y", "\[Prime]", MultilineFunction->None], "[", "x", "]"}], "-", SuperscriptBox[ RowBox[{"y", "[", "x", "]"}], "3"]}], "\[Equal]", "0"}], ",", RowBox[{ RowBox[{ SuperscriptBox["y", "\[Prime]", MultilineFunction->None], "[", "0", "]"}], "\[Equal]", "1"}]}], "}"}], ",", RowBox[{"y", "[", "x", "]"}], ",", "x"}], "]"}]}]], "Input", CellTags->"Calculus"], Cell["\<\ P\[RHacek]\[IAcute]kaz vykresl\[IAcute] graf prvn\[IAcute]ho \[RHacek]e\ \[SHacek]en\[IAcute] v ur\[CHacek]en\[EAcute]m rozsahu.\ \>", "MathCaption", CellChangeTimes->{{3.579843682859375*^9, 3.5798437140625*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Plot", "[", RowBox[{ RowBox[{ RowBox[{"y", "[", "x", "]"}], "/.", "\[InvisibleSpace]", RowBox[{"soln", "[", RowBox[{"[", "1", "]"}], "]"}]}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "5"}], ",", FractionBox["1", "2"]}], "}"}]}], "]"}]], "Input"], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell[TextData[{ StyleBox["Kalkulus: ", "Color7", FontSlant->"Plain"], "Limity a \[RHacek]ady" }], "Subsection", CellChangeTimes->{{3.57984373653125*^9, 3.579843747765625*^9}, { 3.579843996140625*^9, 3.57984400225*^9}}, CellTags->"Calculus"], Cell[TextData[{ "Limity jsou ru\[CHacek]eny pou\[ZHacek]it\[IAcute] funkce ", Cell[BoxData[ ButtonBox["Limit", BaseStyle->"Link", ButtonData->"paclet:ref/Limit"]], "InlineFormula"], "." }], "Text", CellChangeTimes->{{3.5798437515625*^9, 3.579843766859375*^9}}, CellTags->"Calculus"], Cell[TextData[{ "Prom\[EHacek]nn\[AAcute] a hodnota limity je ve funkci ", Cell[BoxData[ ButtonBox["Limit", BaseStyle->"Link", ButtonData->"paclet:ref/Limit"]], "InlineFormula"], " ur\[CHacek]ena pomoc\[IAcute] pravidla." }], "MathCaption", CellChangeTimes->{{3.579843779609375*^9, 3.5798438125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Limit", "[", RowBox[{ FractionBox[ RowBox[{"Sin", "[", "x", "]"}], "x"], ",", RowBox[{"x", "\[Rule]", "0"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "N\[AAcute]sleduj\[IAcute]c\[IAcute] ur\[CHacek]\[IAcute] limitu, ve kter\ \[EAcute] ", Cell[BoxData[ FormBox["x", TraditionalForm]], "None"], " dosahuje ", Cell[BoxData[ FormBox[ RowBox[{"\[Pi]", "/", "2"}], TraditionalForm]]], " men\[SHacek]\[IAcute]mi hodnotami." }], "MathCaption", CellChangeTimes->{{3.5798438509375*^9, 3.579843884453125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Limit", "[", RowBox[{ RowBox[{"Tan", "[", "x", "]"}], ",", RowBox[{"x", "\[Rule]", FractionBox["\[Pi]", "2"]}], ",", RowBox[{"Direction", "\[Rule]", "1"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "Aproximace funkce \[RHacek]adou je ur\[CHacek]ena pomoc\[IAcute] funkce ", Cell[BoxData[ ButtonBox["Series", BaseStyle->"Link", ButtonData->"paclet:ref/Series"]], "InlineFormula"], ". Druh\[YAcute] argument ve funkci ", Cell[BoxData[ ButtonBox["Series", BaseStyle->"Link", ButtonData->"paclet:ref/Series"]], "InlineFormula"], " ur\[CHacek]uje prom\[EHacek]nou, bod, ve kter\[EAcute]m po\[ZHacek]adujeme \ rozvoj p\[RHacek]\[IAcute]slu\[SHacek]n\[EAcute] funkce a stupe\[NHacek] \ rozvoje." }], "MathCaption", CellChangeTimes->{{3.57984389271875*^9, 3.57984401996875*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"expr", "=", RowBox[{"Series", "[", RowBox[{ RowBox[{"Sin", "[", "x", "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "5"}], "}"}]}], "]"}]}]], "Input", CellTags->"Calculus"], Cell[TextData[{ "V\[SHacek]imn\[EHacek]te si, \[ZHacek]e v\[YAcute]raz, kter\[YAcute] vrac\ \[IAcute] funkce ", Cell[BoxData[ ButtonBox["Series", BaseStyle->"Link", ButtonData->"paclet:ref/Series"]], "InlineFormula"], " nen\[IAcute] polynom, ale datov\[YAcute] objekt, kter\[YAcute] je \ optimalizov\[AAcute]n pro pr\[AAcute]ci s ostatn\[IAcute]m v\[YAcute]sledky \ funkce. Pokud pot\[RHacek]ebujeme pracovat s polynomem, je nutn\[EAcute] \ konvertovat datov\[YAcute] objekt na regul\[AAcute]rn\[IAcute] polynom pomoc\ \[IAcute] funkce ", Cell[BoxData[ ButtonBox["Normal", BaseStyle->"Link", ButtonData->"paclet:ref/Normal"]], "InlineFormula"], "." }], "Text", CellChangeTimes->{{3.579844031140625*^9, 3.57984417021875*^9}}, CellTags->"Calculus"], Cell[TextData[{ "Nap\[RHacek]\[IAcute]klad prvn\[IAcute] p\[RHacek]\[IAcute]kaz konvertuje \ aproximaci funkce na polynom a pot\[EAcute] je tento rozvoj vykreslen spolu s \ aproximovanou funkc\[IAcute] ", Cell[BoxData[ FormBox[ RowBox[{"sin", "(", "x", ")"}], TraditionalForm]]], "." }], "MathCaption", CellChangeTimes->{{3.57984417965625*^9, 3.57984423465625*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"poly", "=", RowBox[{"Normal", "[", "expr", "]"}]}]], "Input", CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Plot", "[", RowBox[{ RowBox[{"{", RowBox[{"poly", ",", RowBox[{"Sin", "[", "x", "]"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{ RowBox[{"-", "2"}], "\[Pi]"}], ",", RowBox[{"2", "\[Pi]"}]}], "}"}], ",", RowBox[{"PlotStyle", "\[Rule]", RowBox[{"{", RowBox[{"Red", ",", "Blue"}], "}"}]}]}], "]"}]], "Input", CellTags->"Calculus"], Cell["\<\ Existuje velmi m\[AAcute]lo obecn\[YAcute]ch algoritm\[URing], kter\[EAcute] \ um\[IAcute] ur\[CHacek]it limity nebo rozvoj funkc\[IAcute], pro \ kter\[EAcute] neexistuje mocninn\[YAcute] rozvoj. Pou\[ZHacek]it\[YAcute] \ odpov\[IAcute]daj\[IAcute]c\[IAcute] v\[YAcute]po\[CHacek]et \[CHacek]asto \ sel\[ZHacek]e.\ \>", "MathCaption", CellChangeTimes->{{3.57984429415625*^9, 3.579844367125*^9}}, CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Series", "[", RowBox[{ SuperscriptBox["\[ExponentialE]", FractionBox["1", "x"]], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "1"}], "}"}]}], "]"}]], "Input", CellTags->"Calculus"], Cell["You could compute the series about a symbolic point though.", \ "MathCaption", CellTags->"Calculus"], Cell[BoxData[ RowBox[{"Series", "[", RowBox[{ SuperscriptBox["\[ExponentialE]", FractionBox["1", "x"]], ",", RowBox[{"{", RowBox[{"x", ",", "\[Alpha]", ",", "3"}], "}"}]}], "]"}]], "Input"], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell[CellGroupData[{ Cell["Zjednodu\[SHacek]en\[IAcute] (simplifikace)", "Section", CellChangeTimes->{{3.579844391046875*^9, 3.57984440359375*^9}}, CellTags->"Simplification"], Cell["Obsah", "OverviewSubsection", CellChangeTimes->{{3.579844396703125*^9, 3.579844398640625*^9}}, CellTags->"Simplification"], Cell[CellGroupData[{ Cell[TextData[{ "funkce pro zjednodu\[SHacek]en\[IAcute] v\[YAcute]raz\[URing]\[LongDash]", Cell[BoxData[ ButtonBox["Simplify", BaseStyle->"Link", ButtonData->"paclet:ref/Simplify"]]], ", ", Cell[BoxData[ ButtonBox["FullSimplify", BaseStyle->"Link", ButtonData->"paclet:ref/FullSimplify"]]], ", ", Cell[BoxData[ ButtonBox["TrigExpand", BaseStyle->"Link", ButtonData->"paclet:ref/TrigExpand"]]] }], "Item", CellChangeTimes->{{3.57984440871875*^9, 3.57984442590625*^9}}, CellTags->"Simplification"], Cell["\<\ zjednodu\[SHacek]en\[IAcute] s pou\[ZHacek]it\[IAcute] p\[RHacek]edpoklad\ \[URing]\ \>", "Item", CellChangeTimes->{{3.579844430890625*^9, 3.579844443203125*^9}}, CellTags->"Simplification"], Cell["\<\ doporu\[CHacek]en\[IAcute] pro zjednodu\[SHacek]en\[IAcute] v\[YAcute]raz\ \[URing]\ \>", "Item", CellChangeTimes->{{3.5798444455*^9, 3.57984445665625*^9}}, CellTags->"Simplification"] }, Open ]], Cell[" ", "Spacer"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["", "SlideShowNavigationBar", CellTags->"SlideShowHeader"], Cell["", "Text", CellChangeTimes->{{3.57984503240625*^9, 3.579845033703125*^9}}], Cell[CellGroupData[{ Cell[TextData[StyleBox["Zjednodu\[SHacek]en\[IAcute]", "Color7", FontSlant->"Plain"]], "Subsection", CellChangeTimes->{{3.579844461984375*^9, 3.579844464046875*^9}}, CellTags->"Simplification"], Cell[TextData[{ "Funkce ", Cell[BoxData[ ButtonBox["Simplify", BaseStyle->"Link", ButtonData->"paclet:ref/Simplify"]], "InlineFormula"], " aplikuje na v\[YAcute]raz z\[AAcute]kladn\[IAcute] polynomi\[AAcute]ln\ \[IAcute] operace a dal\[SHacek]\[IAcute] transformace a vrac\[IAcute] \ nejjednodu\[SHacek]\[SHacek]\[IAcute] formu, kterou nalezne." }], "Text", CellChangeTimes->{{3.57984503078125*^9, 3.57984509553125*^9}}, CellTags->"Simplification"], Cell["Vlo\[ZHacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] v\[YAcute]raz.", \ "MathCaption", CellChangeTimes->{{3.579845106203125*^9, 3.579845137*^9}}, CellTags->"Simplification"], Cell[BoxData[ RowBox[{"expr", "=", RowBox[{ SuperscriptBox[ RowBox[{"Cos", "[", "x", "]"}], "2"], "+", RowBox[{"3", " ", SuperscriptBox[ RowBox[{"Cos", "[", "x", "]"}], "2"], " ", RowBox[{"Sin", "[", "x", "]"}]}], "-", SuperscriptBox[ RowBox[{"Sin", "[", "x", "]"}], "2"], "-", SuperscriptBox[ RowBox[{"Sin", "[", "x", "]"}], "3"]}]}]], "Input", CellTags->"Simplification"], Cell[TextData[{ "Funkce ", Cell[BoxData[ ButtonBox["Simplify", BaseStyle->"Link", ButtonData->"paclet:ref/Simplify"]], "InlineFormula"], " jednodu\[SHacek]\[SHacek]\[IAcute] formu v\[YAcute]razu." }], "MathCaption", CellChangeTimes->{{3.57984513953125*^9, 3.5798451574375*^9}}, CellTags->"Simplification"], Cell["Simplify[expr]", "Input", CellTags->"Simplification"], Cell[TextData[{ "Funkce ", Cell[BoxData[ ButtonBox["FullSimplify", BaseStyle->"Link", ButtonData->"paclet:ref/FullSimplify"]], "InlineFormula"], " zkus\[IAcute] v\[IAcute]ce r\[URing]zn\[YAcute]ch transformac\[IAcute]. 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