(* Content-type: application/vnd.wolfram.mathematica *) (*** Wolfram Notebook File ***) (* http://www.wolfram.com/nb *) (* CreatedBy='Mathematica 9.0' *) (*CacheID: 234*) (* Internal cache information: NotebookFileLineBreakTest NotebookFileLineBreakTest NotebookDataPosition[ 157, 7] NotebookDataLength[ 39024, 1056] NotebookOptionsPosition[ 24123, 725] NotebookOutlinePosition[ 34117, 948] CellTagsIndexPosition[ 33810, 937] WindowFrame->Normal*) (* Beginning of Notebook Content *) Notebook[{ Cell[CellGroupData[{ Cell["Zad\[AAcute]n\[IAcute] p\[RHacek]\[IAcute]klad\[URing]", "Section", CellChangeTimes->{{3.572062462421875*^9, 3.572062470796875*^9}}, CounterAssignments->{{"Chapter", 4}, {"ExerciseNumber", 0}}, CellTags->"Exercises"], Cell[TextData[StyleBox["\[CapitalRHacek]e\[SHacek]en\[IAcute] rovnic", \ "Subsection"]], "ExerciseHeading", CellChangeTimes->{{3.57206247509375*^9, 3.57206248725*^9}}, CellTags->{"Exercises", "Solving Equations Ex"}], Cell[TextData[{ "Ur\[CHacek]et hodnoty ", Cell[BoxData[ FormBox["x", TraditionalForm]]], " jako \[RHacek]e\[SHacek]en\[IAcute] rovnice ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ RowBox[{"a", " ", SuperscriptBox["x", "2"]}], "+", RowBox[{"b", " ", "x"}], "+", "c"}], "=", "0"}], TraditionalForm]]], "." }], "Exercise", CellChangeTimes->{{3.5720624973125*^9, 3.572062513765625*^9}}, CellTags->{"Exercises", "Solving Equations Ex"}], Cell[TextData[{ "\n\[CapitalRHacek]e\[SHacek]te nasleduj\[IAcute]c\[IAcute] soustavu rovnice \ pro ", Cell[BoxData[ FormBox["x", TraditionalForm]]], " a ", Cell[BoxData[ FormBox["y", TraditionalForm]]], " a uka\[ZHacek]te, \[ZHacek]e \[RHacek]e\[SHacek]en\[IAcute] vyhovuje \ rovnic\[IAcute]m. Mo\[ZHacek]n\[EAcute] \[RHacek]e\[SHacek]en\[IAcute] je \ substituce pomoc\[IAcute] substitu\[CHacek]n\[IAcute]ho pravidla do \ p\[URing]vodn\[IAcute]ch rovnic a uk\[AAcute]zat, \[ZHacek]e v\[YAcute]sledek \ je True. 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P\[RHacek]eve\[DHacek]te funkci na \ v\[YAcute]raz se spole\[CHacek]n\[YAcute]m jmenovatelem.\ \>", "Exercise", CellChangeTimes->{{3.572062763234375*^9, 3.572062837375*^9}, { 3.578304157015625*^9, 3.578304162875*^9}, 3.578304311796875*^9}, CellTags->{"Exercises", "Rational Functions"}], Cell[BoxData[ RowBox[{"expr", "=", RowBox[{"Sum", "[", RowBox[{ RowBox[{"1", "/", RowBox[{"(", RowBox[{"k", "+", "x"}], ")"}]}], ",", RowBox[{"{", RowBox[{"k", ",", "5"}], "}"}]}], "]"}]}]], "Input", CellTags->{"Exercises", "Rational Functions"}], Cell["", "Exercise", CellChangeTimes->{3.57206286546875*^9}, CellTags->{"Exercises", "Rational Functions"}], Cell[TextData[{ StyleBox["P\[RHacek]eve\[DHacek]te v\[YAcute]sledek zp\[EHacek]t do \ p\[URing]vodn\[IAcute] formy. Operace konverze v\[YAcute]raz\[URing] do p\ \[URing]vodn\[IAcute] formy se naz\[YAcute]v\[AAcute] ", "Exercise"], StyleBox["\[CHacek]\[AAcute]ste\[CHacek]n\[AAcute] dekompozice zlomku.", "Exercise", FontSlant->"Italic"], StyleBox[".", "Exercise"] }], "Exercise", CellChangeTimes->{{3.572062878828125*^9, 3.5720629435625*^9}, { 3.572062985046875*^9, 3.572062992515625*^9}, {3.578304146859375*^9, 3.578304170265625*^9}}, CellTags->{"Exercises", "Rational Functions"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{3.57206294946875*^9}], Cell[TextData[StyleBox["Pou\[ZHacek]it\[IAcute] p\[RHacek]edpoklad\[URing]", \ "Subsection"]], "ExerciseHeading", CellChangeTimes->{{3.572064820171875*^9, 3.572064833046875*^9}}, CellTags->{"Exercises", "Using Assumptions"}], Cell[TextData[{ "Pou\[ZHacek]ij funkci ", Cell[BoxData[ ButtonBox["Simplify", BaseStyle->"Link", ButtonData->"paclet:ref/Simplify"]], "InlineFormula"], " z odpov\[IAcute]daj\[IAcute]c\[IAcute]mi p\[RHacek]edpoklady a \ uka\[ZHacek]te, \[ZHacek]e n\[AAcute]sleduj\[IAcute]c\[IAcute] v\[YAcute]raz \ je 0 pokud ", StyleBox["x", "MR"], " je kladn\[EAcute] a ", StyleBox["n", "MR"], " je cel\[EAcute] \[CHacek]\[IAcute]slo (integer)." }], "Exercise", CellChangeTimes->{{3.572064344109375*^9, 3.572064428046875*^9}}, CellTags->{"Exercises", "Using Assumptions"}], Cell[BoxData[ RowBox[{ RowBox[{"Sqrt", "[", RowBox[{"x", "^", "2"}], "]"}], "-", RowBox[{"x", " ", RowBox[{"Cos", "[", RowBox[{"2", "n", " ", "Pi"}], "]"}]}]}]], "Input", CellTags->{"Exercises", "Using Assumptions"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{{3.57206444328125*^9, 3.572064444296875*^9}}], Cell[TextData[{ "Nastavte hodnoty ", Cell[BoxData[ ButtonBox["Assumptions", BaseStyle->"Link", ButtonData->"paclet:ref/Assumptions"]], "InlineFormula"], " parametru v integr\[AAcute]lu tak, \[ZHacek]e v\[YAcute]sledek je vr\ \[AAcute]cen bez pou\[ZHacek]it\[IAcute] ", Cell[BoxData[ ButtonBox["If", BaseStyle->"Link", ButtonData->"paclet:ref/If"]], "InlineFormula"], " v\[YAcute]razu. " }], "Exercise", CellChangeTimes->{{3.57206447234375*^9, 3.57206455078125*^9}}, CellTags->{"Exercises", "Using Assumptions"}], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{ RowBox[{"Exp", "[", RowBox[{ RowBox[{"-", "b"}], " ", "x"}], "]"}], "/", RowBox[{"(", RowBox[{"x", "+", "c"}], ")"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "Infinity"}], "}"}]}], "]"}]], "Input", CellTags->{"Exercises", "Using Assumptions"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{{3.572064810390625*^9, 3.572064811421875*^9}}], Cell[TextData[StyleBox["Kontrola v\[YAcute]sledk\[URing] symbolick\[YAcute]ch \ v\[YAcute]po\[CHacek]t\[URing] \[CHacek]\[IAcute]seln\[EHacek]", \ "Subsection"]], "ExerciseHeading", CellChangeTimes->{{3.572064842265625*^9, 3.5720648681875*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell["\<\ Jedn\[IAcute]m ze zp\[URing]sob\[URing] kontroly symbolick\[YAcute]ch v\ \[YAcute]po\[CHacek]t\[URing] je substituce symbolick\[YAcute]ch \ v\[YAcute]raz\[URing] \[CHacek]\[IAcute]seln\[YAcute]mi hodnotami a proveden\ \[IAcute] stejn\[EAcute]ho v\[YAcute]po\[CHacek]tu \[CHacek]\[IAcute]seln\ \[EHacek].\ \>", "Text", CellChangeTimes->{{3.57206488784375*^9, 3.57206495646875*^9}, { 3.57830482190625*^9, 3.578304821984375*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Nap\[RHacek]\[IAcute]klad, vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\ \[IAcute] vstup, aby jste obdr\[ZHacek]eli v\[YAcute]sledek integrace z\ \[AAcute]visl\[YAcute] na parametru ", StyleBox["b", "MR"], "." }], "Exercise", CellChangeTimes->{{3.572064958484375*^9, 3.572065005828125*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[BoxData[ RowBox[{"int", "=", RowBox[{"Integrate", "[", RowBox[{ RowBox[{ RowBox[{"Exp", "[", RowBox[{"-", "x"}], "]"}], "/", RowBox[{"(", RowBox[{"1", "+", RowBox[{"b", " ", "x"}]}], ")"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "Infinity"}], "}"}], ",", RowBox[{"Assumptions", "\[Rule]", RowBox[{"b", ">", "0"}]}]}], "]"}]}]], "Input", CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Tento integr\[AAcute]l m\[URing]\[ZHacek]e b\[YAcute]t vypo\[CHacek]ten \ \[CHacek]\[IAcute]seln\[EHacek] pomoc\[IAcute] funkce ", Cell[BoxData[ ButtonBox["NIntegrate", BaseStyle->"Link", ButtonData->"paclet:ref/NIntegrate"]], "InlineFormula"], " pokud je symbolick\[YAcute] parametr zad\[AAcute]n jako \ \[CHacek]\[IAcute]seln\[AAcute] hodnota. Sp\[IAcute]\[SHacek]e ne\[ZHacek] \ zad\[AAcute]vat jednu hodnotu argumentu na vstup je vhodn\[EHacek]j\[SHacek]\ \[IAcute] pou\[ZHacek]\[IAcute]t p\[RHacek]\[IAcute]stup, p\[RHacek]i kter\ \[EAcute]m je mo\[ZHacek]n\[EAcute] zadat v\[IAcute]ce hodnot parametru \ najednou. " }], "Text", CellChangeTimes->{{3.572065025203125*^9, 3.572065165171875*^9}, 3.5783048485*^9}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] vstup a \ obdr\[ZHacek]\[IAcute]te hodnotu integr\[AAcute]lu pro hodnotu ", StyleBox["b", "MR"], " rovnou 3. Hodnota parametru ", StyleBox["b", "MR"], " je zad\[AAcute]na pomoc\[IAcute] ", Cell[BoxData[ ButtonBox["Block", BaseStyle->"Link", ButtonData->"paclet:ref/Block"]], "InlineFormula"], "." }], "Exercise", CellChangeTimes->{{3.572065168640625*^9, 3.57206523221875*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[BoxData[ RowBox[{"Block", "[", RowBox[{ RowBox[{"{", RowBox[{"b", "=", "3"}], "}"}], ",", RowBox[{"NIntegrate", "[", RowBox[{ RowBox[{ RowBox[{"Exp", "[", RowBox[{"-", "x"}], "]"}], "/", RowBox[{"(", RowBox[{"1", "+", RowBox[{"b", " ", "x"}]}], ")"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "Infinity"}], "}"}]}], "]"}]}], "]"}]], "Input", CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] vstup a \ ur\[CHacek]ete \[CHacek]\[IAcute]selnou aproximaci symbolick\[EAcute]ho v\ \[YAcute]sledku pro stejnou hodnotu ", StyleBox["b", "MR"], ". Srovnejte v\[YAcute]sledek s v\[YAcute]stupem \[CHacek]\[IAcute]seln\ \[EAcute] integrace z p\[RHacek]edch\[AAcute]zej\[IAcute]c\[IAcute]ho. " }], "Exercise", CellChangeTimes->{{3.572065494171875*^9, 3.572065609296875*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[BoxData[ RowBox[{"Block", "[", RowBox[{ RowBox[{"{", RowBox[{"b", "=", "3"}], "}"}], ",", RowBox[{"N", "[", "int", "]"}]}], "]"}]], "Input", CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{3.572065613078125*^9}], Cell[TextData[{ "Tyto dva v\[YAcute]po\[CHacek]ty (\[CHacek]\[IAcute]seln\[AAcute] integrace \ pomoc\[IAcute] ", Cell[BoxData[ ButtonBox["NIntegrate", BaseStyle->"Link", ButtonData->"paclet:ref/NIntegrate"]], "InlineFormula"], " a \[CAcute]\[IAcute]seln\[AAcute] aproximace v\[YAcute]sledk funkce ", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]], "InlineFormula"], ") m\[URing]\[ZHacek]eme zkombinovat do jednoho v\[YAcute]sledku, kter\ \[YAcute] vr\[AAcute]t\[IAcute] ob\[EHacek] \[RHacek]e\[SHacek]en\[IAcute]." }], "Text", CellChangeTimes->{{3.5720656166875*^9, 3.57206570675*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Vyhodnott\[EAcute] n\[AAcute]sleduj\[IAcute]c\[IAcute] vstup a srovnejte v\ \[YAcute]stup z funkce ", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]], "InlineFormula"], " v\[YAcute]stup z funkce ", Cell[BoxData[ ButtonBox["NIntegrate", BaseStyle->"Link", ButtonData->"paclet:ref/NIntegrate"]], "InlineFormula"], ". " }], "Exercise", CellChangeTimes->{{3.5720657113125*^9, 3.572065748375*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[BoxData[ RowBox[{"Block", "[", RowBox[{ RowBox[{"{", RowBox[{"b", "=", "3"}], "}"}], ",", RowBox[{"{", RowBox[{ RowBox[{"N", "[", "int", "]"}], ",", RowBox[{"NIntegrate", "[", RowBox[{ RowBox[{ RowBox[{"Exp", "[", RowBox[{"-", "x"}], "]"}], "/", RowBox[{"(", RowBox[{"1", "+", RowBox[{"b", " ", "x"}]}], ")"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "Infinity"}], "}"}]}], "]"}]}], "}"}]}], "]"}]], "Input", CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Pou\[ZHacek]ijte popsanou strategii ke kontrole n\[AAcute]sleduj\[IAcute]c\ \[IAcute]ho v\[YAcute]stupu funkce ", Cell[BoxData[ ButtonBox["Integrate", BaseStyle->"Link", ButtonData->"paclet:ref/Integrate"]], "InlineFormula"], ". V\[SHacek]imn\[EHacek]te si, \[ZHacek]e v\[YAcute]stup obsahuje dva \ symbolick\[EAcute] parametry ", StyleBox["b", "MR"], " a ", StyleBox["x1", "MR"], "." }], "Exercise", CellChangeTimes->{{3.572065779296875*^9, 3.572065856078125*^9}}, CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[BoxData[ RowBox[{"Integrate", "[", RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], " ", RowBox[{"Cos", "[", RowBox[{"x", "+", "b"}], "]"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "x1"}], "}"}]}], "]"}]], "Input", CellTags->{"Exercises", "Checking Symbolic Results"}], Cell[TextData[{ "Pou\[ZHacek]ijte funkci Manipulate pro nastaven\[IAcute] r\[URing]zn\ \[YAcute]ch hodnot parametr\[URing] b a x1.\n\n", StyleBox["\[CapitalRHacek]e\[SHacek]en\[IAcute] line\[AAcute]rn\[IAcute]ch \ rovnic", "Subsection"] }], "ExerciseHeading", CellChangeTimes->{{3.5720659655*^9, 3.572066022078125*^9}}, CellTags->{"Exercises", "Solving Linear Equations"}], Cell[TextData[{ "Vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] dva vstupy a \ zkonstruujte mno\[ZHacek]inu line\[AAcute]rn\[IAcute]ch rovnic \ prom\[EHacek]nn\[YAcute]ch ", StyleBox["x1", "MR"], ", ", StyleBox["x2", "MR"], ", ", StyleBox["x3", "MR"], ", a ", StyleBox["x4", "MR"], ". Prvn\[IAcute] v\[YAcute]raz zkonstruuje matici koeficient\[URing] ", StyleBox["m", "MR"], ", a druh\[YAcute] v\[YAcute]raz pou\[ZHacek]ijte tyto koeficienty ke \ konstrukci rovnic." }], "Exercise", CellChangeTimes->{{3.5720660510625*^9, 3.57206616559375*^9}, 3.57830556621875*^9}, CellTags->{"Exercises", "Solving Linear Equations"}], Cell[BoxData[ RowBox[{"m", "=", RowBox[{"(", RowBox[{ RowBox[{"b", " ", RowBox[{"IdentityMatrix", "[", "4", "]"}]}], "-", RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"0", ",", "1", ",", "0", ",", "0"}], "}"}], ",", RowBox[{"{", RowBox[{"0", ",", "0", ",", "1", ",", "0"}], "}"}], ",", RowBox[{"{", RowBox[{"0", ",", "0", ",", "0", ",", "1"}], "}"}], ",", RowBox[{"{", RowBox[{"1", ",", "0", ",", "0", ",", "0"}], "}"}]}], "}"}]}], ")"}]}]], "Input", CellTags->{"Exercises", "Solving Linear Equations"}], Cell[BoxData[ RowBox[{"eq", "=", RowBox[{ RowBox[{"m", ".", RowBox[{"{", RowBox[{"x1", ",", "x2", ",", "x3", ",", "x4"}], "}"}]}], "\[Equal]", RowBox[{"{", RowBox[{"1", ",", "0", ",", "0", ",", "0"}], "}"}]}]}]], "Input", CellTags->{"Exercises", "Solving Linear Equations"}], Cell[TextData[{ "Uka\[ZHacek]te \[RHacek]e\[SHacek]en\[IAcute] t\[EHacek]chto rovnic s pou\ \[ZHacek]it\[IAcute]m funkce ", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], "." }], "Exercise", CellChangeTimes->{{3.572066249671875*^9, 3.572066275953125*^9}}, CellTags->{"Exercises", "Solving Linear Equations"}], Cell[TextData[{ "Nyn\[IAcute] \[RHacek]e\[SHacek]te stejnou soustavu rovnic pomoc\[IAcute] \ funkce ", Cell[BoxData[ ButtonBox["LinearSolve", BaseStyle->"Link", ButtonData->"paclet:ref/LinearSolve"]], "InlineFormula"], ". na rozd\[IAcute]l od funkce ", Cell[BoxData[ ButtonBox["Solve", BaseStyle->"Link", ButtonData->"paclet:ref/Solve"]], "InlineFormula"], ", ve kter\[EAcute] jsou argumenty rovnice, argumenty funkce ", Cell[BoxData[ ButtonBox["LinearSolve", BaseStyle->"Link", ButtonData->"paclet:ref/LinearSolve"]], "InlineFormula"], " jsou koeficienty rovnice.. V\[YAcute]sledek je tak\[EAcute] vr\[AAcute]cen \ v odli\[SHacek]n\[EAcute] form\[EHacek]. " }], "Exercise", CellChangeTimes->{{3.572066366265625*^9, 3.572066474078125*^9}}, CellTags->{"Exercises", "Solving Linear Equations"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{3.572066488359375*^9}], Cell[TextData[StyleBox["Pr\[AAcute]ce s \[RHacek]adami rozvoje \ funkc\[IAcute]", "Subsection"]], "ExerciseHeading", CellChangeTimes->{{3.57206649325*^9, 3.5720665470625*^9}}, CellTags->{"Exercises", "Series Expansions"}], Cell[TextData[{ "Vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] t\[RHacek]i vstupy, \ kter\[EAcute] generuj\[IAcute] rozvoj funkce ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], " do stupn\[EHacek] to 10 v okol\[IAcute] 0 a nakresl\[IAcute] graf, kter\ \[YAcute] srovn\[AAcute]v\[AAcute] tento polynomi\[AAcute]ln\[IAcute] rozvoj \ a vlastn\[IAcute] funkci ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], ". Jak\[YAcute] efekt m\[AAcute] pou\[ZHacek]it\[IAcute] funkce ", Cell[BoxData[ ButtonBox["Normal", BaseStyle->"Link", ButtonData->"paclet:ref/Normal"]], "InlineFormula"], " ve v\[YAcute]po\[CHacek]tu? Co se stane, pokud aplikaci funkce ", Cell[BoxData[ ButtonBox["Normal", BaseStyle->"Link", ButtonData->"paclet:ref/Normal"]], "InlineFormula"], " vynech\[AAcute]me? Pro\[CHacek]?" }], "Exercise", CellChangeTimes->{{3.572066548859375*^9, 3.5720666995*^9}, { 3.578305936484375*^9, 3.57830594071875*^9}}, CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[ RowBox[{"ser", "=", RowBox[{"Series", "[", RowBox[{ RowBox[{"Cos", "[", "x", "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "10"}], "}"}]}], "]"}]}]], "Input", CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[ RowBox[{"poly", "=", RowBox[{"Normal", "[", "ser", "]"}]}]], "Input", CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[ RowBox[{"Plot", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{"Cos", "[", "x", "]"}], ",", "poly"}], "}"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "8"}], "}"}]}], "]"}]], "Input", CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{3.572066758203125*^9}], Cell[TextData[{ "Vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] vstup. kter\[YAcute] \ vy\[CHacek]\[IAcute]sl\[IAcute] rozd\[IAcute]l mezi funkc\[IAcute] ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], " a jej\[IAcute]m rozvojem 10. stupn\[EHacek] v okol\[IAcute] 0. \ Jak\[YAcute] je v\[YAcute]znam pou\[ZHacek]it\[IAcute] ", Cell[BoxData[ ButtonBox["Normal", BaseStyle->"Link", ButtonData->"paclet:ref/Normal"]], "InlineFormula"], " v tomto vstupu? Co se stane, pokud funkci ", Cell[BoxData[ ButtonBox["Normal", BaseStyle->"Link", ButtonData->"paclet:ref/Normal"]], "InlineFormula"], " vynech\[AAcute]me? Pro\[CHacek]?" }], "Exercise", CellChangeTimes->{{3.57206676084375*^9, 3.57206687940625*^9}}, CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[ RowBox[{ RowBox[{"Normal", "[", RowBox[{"Series", "[", RowBox[{ RowBox[{"Cos", "[", "x", "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "10"}], "}"}]}], "]"}], "]"}], "-", RowBox[{"Cos", "[", "x", "]"}]}]], "Input", CellChangeTimes->{{3.5720672576875*^9, 3.5720672689375*^9}}, CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{3.572066931421875*^9}], Cell[TextData[{ "Vyhodno\[THacek]te n\[AAcute]sleduj\[IAcute]c\[IAcute] vstup a definujte \ funkci ", Cell[BoxData[ RowBox[{"f", "[", RowBox[{"n", ",", "x"}], "]"}]]], ", kter\[AAcute] vrac\[IAcute] rozd\[IAcute]l mezi ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], "a rozvojem ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], " n-t\[EAcute]ho stupn\[EHacek] v okol\[IAcute] ", StyleBox["x", "MR"], "." }], "Exercise", CellChangeTimes->{{3.5720669454375*^9, 3.572067017171875*^9}}, CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[ RowBox[{ RowBox[{"f", "[", RowBox[{"n_", ",", "x_"}], "]"}], ":=", RowBox[{"Module", "[", RowBox[{ RowBox[{"{", "t", "}"}], ",", RowBox[{ RowBox[{ RowBox[{"Normal", "[", RowBox[{"Series", "[", RowBox[{ RowBox[{"Cos", "[", "t", "]"}], ",", RowBox[{"{", RowBox[{"t", ",", "0", ",", "n"}], "}"}]}], "]"}], "]"}], "-", RowBox[{"Cos", "[", "x", "]"}]}], "/.", RowBox[{"t", "\[Rule]", "x"}]}]}], "]"}]}]], "Input", CellChangeTimes->{{3.572067169203125*^9, 3.57206717128125*^9}, { 3.57206720503125*^9, 3.572067206578125*^9}, {3.572067523234375*^9, 3.5720675516875*^9}}, CellTags->{"Exercises", "Series Expansions"}], Cell[TextData[{ "\nJak\[YAcute] je d\[URing]vod pou\[ZHacek]it\[IAcute] prom\[EHacek]nn\ \[EAcute] ", StyleBox["t", "MR"], " v definici funkce ", Cell[BoxData[ RowBox[{"f", "[", RowBox[{"n", ",", "x"}], "]"}]]], "? Bude tato definice funk\[CHacek]n\[IAcute], pokud argument ", StyleBox["x", "MR"], " v ", Cell[BoxData[ RowBox[{"f", "[", RowBox[{"n", ",", "x"}], "]"}]]], " je \[CHacek]\[IAcute]slo?" }], "Exercise", CellChangeTimes->{{3.5720670470625*^9, 3.5720671254375*^9}, 3.57206728459375*^9}, CellTags->{"Exercises", "Series Expansions"}], Cell[BoxData[""], "NonPrintButton", CellChangeTimes->{3.572067156*^9}], Cell[TextData[{ "N\[AAcute]sleduje dal\[SHacek]\[IAcute] funkce ", Cell[BoxData[ RowBox[{"g", "[", RowBox[{"n", ",", "x"}], "]"}]]], ", kter\[AAcute] vrac\[IAcute] rozd\[IAcute]l mezi ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], " a rozvoj ", StyleBox["n", "MR"], " -t\[EAcute]ho stupn\[EHacek] funkce ", Cell[BoxData[ RowBox[{"Cos", "[", "x", "]"}]]], " v okol\[IAcute] ", StyleBox["x", "MR"], ". Tato definice je podobn\[AAcute] definici funkce ", Cell[BoxData[ RowBox[{"f", "[", RowBox[{"n", ",", "x"}], "]"}]]], " s t\[IAcute]m, \[ZHacek]e prom\[EHacek]nn\[AAcute] ", StyleBox["t", "MR"], " nen\[IAcute] pou\[ZHacek]ita. 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